0=x^2+7x-44

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Solution for 0=x^2+7x-44 equation:



0=x^2+7x-44
We move all terms to the left:
0-(x^2+7x-44)=0
We add all the numbers together, and all the variables
-(x^2+7x-44)=0
We get rid of parentheses
-x^2-7x+44=0
We add all the numbers together, and all the variables
-1x^2-7x+44=0
a = -1; b = -7; c = +44;
Δ = b2-4ac
Δ = -72-4·(-1)·44
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*-1}=\frac{-8}{-2} =+4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*-1}=\frac{22}{-2} =-11 $

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